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File.Name

property · File · cAlgo.API Since 5.7

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Gets file name without path.

Definition

string Name {get;}
file.Name: str

Returns string

Examples

protected override void OnStart()
{
    Print("File name: {0}", DataFile.Name);
}
api.Print(f"File name: {api.DataFile.Name}")
{
  "Parameters": [
    {
      "Name": "DataFile",
      "DisplayName": "Data File",
      "Type": "File"
    }
  ]
}